Let be a Normed Space. The unit ball of is: Can check that is closed, bounded, convex, symmetric and a neighbourhood of 0. Lemma Let be a Vector Space over or . If is closed, bounded, convex, symmetric and a Neighbourhood of then defines a Norm by taking: Furthermore, is the unit ball in this norm. Theorem Let be an -dimensional Normed Space. Then there are some with for all and for all . In particular, is not Complete.