Given prime
Suppose
such that
Then
Proof
Repeat the following until our family is empty.
At stage
and denote it by
such that
Thus we find
but adding any new set from our remaining family,
the intersection must be in
By assumption
Set
and remove all these sets
and proceed to stage
We end up with subfamily
and
but for any
Now define
Note
Define linear functionals
and observe they satisfy the conditions of Diagonal Principle;
so the
But the
so spanned by
monomials.
However, over
So
So they are also linearly independent, but spanned by
of size
Therefore