Let
Then for any Function
there is unique
where
Theorem
Say
where the domain of
(Note that
WTS that there is a unique attempt whose domain is
We first show that if
Fix
Assume
(Note that
We have
To complete the proof of existence, we let
Now just check that this is a Function and check that
To find the domain of
If
So there is no attempt defined at
but we know how to do one step extension so this is untrue