Let be a Group and the set of Sylow Subgroups. Then all elements of are Conjugate.

Proof

We prove a stronger statement (DONT NEED TO). Suppose and is a -subgroup. Then for some . Consider the Group action of on left cosets of by left multiplication. Note that , so there is at least one Orbit not divisible by . But all orbits divide , so there is an orbit of size . So for some , and every we have i.e. . Hence for some we have .