Consider

Suppose

with and Suppose also either:

Proof / Method

No elegance, just suffering

Split the problem

We expect to be the main contribution, and small.

is small

Case 1

Assuming we can integrate this and get ie #

Case 2

So

In both cases, is small beyond all orders.

contribution

Want to show

Using a property of The Gamma Function we find that the numerator is equal to:

Now estimate

as . Let and introduce s.t. Get:

for some constant, so as So as


For we note:

So

So

So as for all . Finally:

but