The unique solution to interpolation of at points is given by: where are Lagrange Cardinal Polynomials.

Divided difference

is the coefficient next to in the polynomial which interpolates at points .

Suppose interpolates at , while interpolates at . Then interpolates at . Hence the recurrence formula holds:

The Newton formula

interpolates at .

Proof

By induction: Suppose interpolates at . Then has degree (at most) and roots at for (by induction hypothesis). So it has to be .

Errors

Define the error functions . It has roots in , hence has at least one root . Then or for some in the interval. Furthermore, where interpolates at . So certainly:

On interval , is minimized for (scaled) Chebyshev polynomials (proof by contradiction, using that roots alternate in sign), so and we have