Want to find the dual space of .
For each , have with .
Proposition
Norm of is .
Proof
Have (Hölder inequality)
Given let (the obvious choice, because we want it to converge in )
So so with
Have
( because )
So
Hence
Theorem
The map is an isometric isomorphism (ie they are the same spaces)
Proof
linear, as
isometry as (so is injective) (???)
Need surjective
Given let each 1
want and
For some fixed , let:
Then with
Also
ie so with as is arbitrary
Finally on for all
so on (notation for linear span)
is linear and continuous
ie on the whole of .