Let and be Categories Let and be Functors We say that is left adjoint to and is right adjoint to if

naturally in and . We write An adjunction between and is this Isomorphism. There are two other characterisations of adjunction: Comma Category Triangular Identities

what does naturally mean?

If and were Locally Small, we could express it as a Natural Isomorphism

as functors . If they are not locally small we can express this in elementary terms as follows. For in denote by the corresponding Morphism in Similarly, for any denote by

Naturality means that for any and we have

or equivalently

Note that I actually couldn’t write anything else sensible with these symbols. This is because its the only “natural” thing to write down.

Corollary

If and are both left Adjoint to then and are Isomorphic in

Proof

For any , and are both Initial objects of the Comma Category So there’s a unique Isomorphism . Given , the composites and are both morphisms in so they’re equal.

Lemma

Suppose given and with and . Then

Proof

We have bijections which are natural in both and .

Corollary

Suppose we are given a Commutative Diagram

\usepackage{tikz-cd}
\begin{document}
\begin{tikzcd}
\mathcal{C} \arrow[r,"F"] \arrow[d,"G"]
 & \mathcal{D} \arrow[d,"H"] \\
 \mathcal{E}\arrow[r,"K"]
 & \mathcal{F}
\end{tikzcd}
\end{document}

in which all four Functors have left Adjoints. Then the square of left adjoints commutes up to Natural Isomorphism.

Proof

The two ways round it are both left Adjoint to . So they must be Isomorphic.