If Zermelo-Fraenkel Set Theory is consistent, then Axiom of Choice is consistent:
Proof
Suppose
(in the meta-theory).
Let
We can provide a Well-Order of
and then write for
Make this into an end-extension of
Thus
is a well-order of
and thus
As
If Zermelo-Fraenkel Set Theory is consistent, then Axiom of Choice is consistent:
Suppose
(in the meta-theory).
Let
We can provide a Well-Order of
and then write for
Make this into an end-extension of
Thus
is a well-order of
and thus
As