Let and assume that has -Chain Condition.
Then there are at most
nice names for subsets of .
Proof
Each Strong Antichain in has at most elements,
so there are at most antichains.
But then there are at most families of antichains,
so at most that many nice names.
Fix for some Name.
Suppose that is not a nice name.
Fix .
Then if and only if some forces .
Using Zorn’s Lemma in ,
build a maximal Strong Antichain.
Thus we find
By the lemma in Dense Below, if
then there is some with for all .
So find with .
Then is a larger antichain with .
Therefore, we could have WLOG taken .
But then so